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Keone is driving cross-country. The engine burns
7.5L of fuel every
100km. So far, they burned
37.5L of fuel.
The following equation describes this situation.

-37.5÷-7.5=5
What does 5 tell us?
Choose 1 answer:
A Keone has driven for 5 hundred kilometers.
(B) Keone has driven for 5 hours.
(C) Keone can drive
5km per liter of fuel.

Keone is driving cross-country. The engine burns $7.5 \mathrm{~L}$ of fuel every $100 \mathrm{~km}$ . So far, they burned $37.5 \mathrm{~L}$ of fuel. $\newline$ The following equation describes this situation. $\newline$ $-37.5 \div-7.5=5$ $\newline$ What does $5$ tell us? $\newline$ Choose $1$ answer: $\newline$ (A) Keone has driven for $5$ hundred kilometers. $\newline$ (B) Keone has driven for $5$ hours. $\newline$ (C) Keone can drive $5 \mathrm{~km}$ per liter of fuel.

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Solve a system of equations using any method: word problems

Full solution

Q. Keone is driving cross-country. The engine burns

7.5 \mathrm{~L}

of fuel every

100 \mathrm{~km}

. So far, they burned

37.5 \mathrm{~L}

of fuel.

\newline

The following equation describes this situation.

\newline

-37.5 \div-7.5=5

\newline

What does

5

tell us?

\newline

Choose

1

answer:

\newline

(A) Keone has driven for

5

hundred kilometers.

\newline

(B) Keone has driven for

5

hours.

\newline

(C) Keone can drive

5 \mathrm{~km}

per liter of fuel.

Given fuel consumption rate: Keone's fuel consumption is $7.5\,\text{L}$ per $100\,\text{km}$ , and they've used $37.5\,\text{L}$ so far.
Calculate distance driven: To find out how far Keone has driven, we divide the total fuel used by the fuel consumption rate. $37.5 \div 7.5 = 5$
Divide total fuel used: The result, $5$ , represents the number of $100\,\text{km}$ units Keone has driven because the rate is per $100\,\text{km}$ .
Calculate total distance driven: So, Keone has driven $5 \times 100\,\text{km}$ , which is $500\,\text{km}$ .

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