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(-8)-(6+30 i)=
Express your answer in the form 
(a+bi).

(8)(6+30i)= (-8)-(6+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (8)(6+30i)= (-8)-(6+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Subtracting Complex Number: We need to subtract the complex number (6+30i)(6+30i) from the real number 8-8. To do this, we subtract the real parts and the imaginary parts separately.\newline8(6+30i)=(86)+(30i)-8 - (6 + 30i) = (-8 - 6) + (-30i)
  2. Performing Subtraction: Now we perform the subtraction for the real parts and the imaginary parts.\newline(86)+(30i)=1430i(-8 - 6) + (-30i) = -14 - 30i
  3. Expressing Result: We have expressed the result in the form a+bia+bi, where aa is the real part and bb is the coefficient of the imaginary part ii. So, the result is 1430i -14 - 30i.

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