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Karl had planned to drive for
10(2)/(3) hours on a certain day during his road trip. When he became sleepy, however, he decided to decrease his driving time by
25% that day. How long did Karl decide to drive the day?
A.
2(2)/(3) hours
B. 8 hours
C. 9 hours
D.
13(1)/(3) hours
10

$5$ . Karl had planned to drive for $10 \frac{2}{3}$ hours on a certain day during his road trip. When he became sleepy, however, he decided to decrease his driving time by $25 \%$ that day. How long did Karl decide to drive the day? $\newline$ A. $2 \frac{2}{3}$ hours $\newline$ B. $8$ hours $\newline$ C. $9$ hours $\newline$ D. $13 \frac{1}{3}$ hours $\newline$ $10$

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Add and subtract decimals: word problems

Full solution

Q.

5

. Karl had planned to drive for

10 \frac{2}{3}

hours on a certain day during his road trip. When he became sleepy, however, he decided to decrease his driving time by

25 \%

that day. How long did Karl decide to drive the day?

\newline

A.

2 \frac{2}{3}

hours

\newline

B.

8

hours

\newline

C.

9

hours

\newline

D.

13 \frac{1}{3}

hours

\newline

10

Convert to Improper Fraction: Convert Karl's planned driving time from mixed fraction to an improper fraction. $\newline$ Calculation: $10\frac{2}{3} = 10 \times \frac{3}{3} + \frac{2}{3} = \frac{30}{3} + \frac{2}{3} = \frac{32}{3}$ hours
Calculate Decrease Time: Calculate the amount of time to decrease from the original driving time by finding $25$ % of Karl's planned driving time. $\newline$ Calculation: $25\% \times \frac{32}{3} = \frac{1}{4} \times \frac{32}{3} = \frac{32}{12} = \frac{8}{3}$ hours
Subtract to Find New Time: Subtract the decrease from the original planned driving time to find the new driving time. $\newline$ Calculation: $\frac{32}{3} - \frac{8}{3} = \frac{24}{3} = 8$ hours

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