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Chidi puts
2(3)/(5)kg of bird seed in his large feeder. This is
1(3)/(10) times as much seed as he puts in his smaller feeder.
How much bird seed does Chidi put in his smaller feeder?

kg

Chidi puts $2 \frac{3}{5} \mathrm{~kg}$ of bird seed in his large feeder. This is $1 \frac{3}{10}$ times as much seed as he puts in his smaller feeder. $\newline$ How much bird seed does Chidi put in his smaller feeder? $\newline$ $\mathrm{kg}$

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Add and subtract decimals: word problems

Full solution

Q. Chidi puts

2 \frac{3}{5} \mathrm{~kg}

of bird seed in his large feeder. This is

1 \frac{3}{10}

times as much seed as he puts in his smaller feeder.

\newline

How much bird seed does Chidi put in his smaller feeder?

\newline

\mathrm{kg}

Convert to Improper Fractions: Convert the mixed numbers to improper fractions. $\newline$ $2\left(\frac{3}{5}\right)$ kg can be converted to an improper fraction by multiplying the whole number by the denominator and adding the numerator, then placing the result over the original denominator. $\newline$ $2\left(\frac{3}{5}\right) = \left(2\times 5 + 3\right)/5 = \left(10 + 3\right)/5 = \frac{13}{5}$ kg. $\newline$ $1\left(\frac{3}{10}\right)$ times can be converted similarly. $\newline$ $1\left(\frac{3}{10}\right) = \left(1\times 10 + 3\right)/10 = \left(10 + 3\right)/10 = \frac{13}{10}$ .
Set Up Equation: Set up the equation to find the amount of seed Chidi puts in his smaller feeder. Let $x$ be the amount of seed Chidi puts in his smaller feeder. According to the problem, $2\left(\frac{3}{5}\right)$ kg is $1\left(\frac{3}{10}\right)$ times as much as $x$ . So, we have the equation: $x \times \frac{13}{10} = \frac{13}{5}$ .
Solve for x: Solve for x by dividing both sides of the equation by $\frac{13}{10}$ . To isolate $x$ , we need to divide both sides by $\frac{13}{10}$ , which is the same as multiplying by the reciprocal, $\frac{10}{13}$ . $x = \left(\frac{13}{5}\right) * \left(\frac{10}{13}\right)$ .
Simplify Equation: Simplify the equation by canceling out the common factors. $\newline$ The $13$ in the numerator and the $13$ in the denominator cancel each other out, so we are left with: $\newline$ $x = (\frac{1}{5}) \times 10 = \frac{10}{5}$ .
Final Answer: Simplify $10/5$ to get the final answer. $\newline$ $10/5$ simplifies to $2$ . $\newline$ So, Chidi puts $2$ kg of bird seed in his smaller feeder.

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