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IXL - Equations of parallel an ByteLearn ×1+ larr rarr C :' ixl.com/math/geometry/equations-of-parallel-and-perpendicular-lines 7th Grade Science... Microsoft Forms (144) Hot Wheels... 宜家VIMLE 维姆勒.. Quizizz Creator New Tab GeoGebra - the w... Research for Scien.. Geometry - GeoG... All Bookmarks My IXL Learning Assessment Analytics Harry Geometry > E. 5 Equations of parallel and perpendicular lines VEB Video (D) Questions answered The equation for line c can be written as y=-(3)/(7)x+4. Perpendicular to line c is line d, which passes through the point (2,4). What is the equation of line d ? 847 Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers. Submit Submit 14 Work it out Not feeling ready yet? These can help: Slopes of parallel and perpendicular lines (83) N Equations of lines (26) Lesson: Equations of parallel and perpendicular lines

IXL - Equations of parallel an\newlineByteLearn\newline×1+ \times 1+ \newline←→ \leftarrow \rightarrow C ∵ \because ixl.com/math/geometry/equations-of-parallel-and-perpendicular-lines\newline77th Grade Science...\newlineMicrosoft Forms\newline(144144) Hot Wheels...\newline宜家VIMLE 维姆勒..\newlineQuizizz Creator\newlineNew Tab\newlineGeoGebra - the w...\newlineResearch for Scien..\newlineGeometry - GeoG...\newlineAll Bookmarks\newlineMy IXL Learning Assessment Analytics\newlineHarry\newlineGeometry > > E. 55 Equations of parallel and perpendicular lines VEB\newlineVideo (D)\newlineQuestions\newlineanswered\newlineThe equation for line c c can be written as y=−37x+4 y=-\frac{3}{7} x+4 . Perpendicular to line c c is line d d , which passes through the point (2,4) (2,4) . What is the equation of line d d ?\newline847847\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.\newlineSubmit\newlineSubmit\newline1414\newlineWork it out\newlineNot feeling ready yet? These can help:\newlineSlopes of parallel and perpendicular lines (8383) ←→ \leftarrow \rightarrow 00\newlineEquations of lines (2626)\newlineLesson: Equations of parallel and perpendicular lines

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Q. IXL - Equations of parallel an\newlineByteLearn\newline×1+ \times 1+ \newline←→ \leftarrow \rightarrow C ∵ \because ixl.com/math/geometry/equations-of-parallel-and-perpendicular-lines\newline77th Grade Science...\newlineMicrosoft Forms\newline(144144) Hot Wheels...\newline宜家VIMLE 维姆勒..\newlineQuizizz Creator\newlineNew Tab\newlineGeoGebra - the w...\newlineResearch for Scien..\newlineGeometry - GeoG...\newlineAll Bookmarks\newlineMy IXL Learning Assessment Analytics\newlineHarry\newlineGeometry > > E. 55 Equations of parallel and perpendicular lines VEB\newlineVideo (D)\newlineQuestions\newlineanswered\newlineThe equation for line c c can be written as y=−37x+4 y=-\frac{3}{7} x+4 . Perpendicular to line c c is line d d , which passes through the point (2,4) (2,4) . What is the equation of line d d ?\newline847847\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.\newlineSubmit\newlineSubmit\newline1414\newlineWork it out\newlineNot feeling ready yet? These can help:\newlineSlopes of parallel and perpendicular lines (8383) ←→ \leftarrow \rightarrow 00\newlineEquations of lines (2626)\newlineLesson: Equations of parallel and perpendicular lines
  1. Find Slope of Line c: The equation for line c is given as y=−(37)x+4y = -\left(\frac{3}{7}\right)x + 4. To find the equation of a line d that is perpendicular to line c, we first need to determine the slope of line c. The slope of line c is the coefficient of xx, which is −(37)-\left(\frac{3}{7}\right). Since line d is perpendicular to line c, its slope will be the negative reciprocal of the slope of line c. The negative reciprocal of −(37)-\left(\frac{3}{7}\right) is 73\frac{7}{3}.
  2. Determine Slope of Line d: Now that we have the slope of line d, which is 73\frac{7}{3}, we can use the point-slope form of the equation of a line to find the equation of line d. The point-slope form is y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line. We know that line d passes through the point (2,4)(2,4), so we can substitute m=73m = \frac{7}{3}, x1=2x_1 = 2, and y1=4y_1 = 4 into the point-slope form.
  3. Use Point-Slope Form: Substituting the values into the point-slope form, we get y−4=(73)(x−2)y - 4 = \left(\frac{7}{3}\right)(x - 2). Now we need to simplify this equation to get it into slope-intercept form, which is y=mx+by = mx + b.
  4. Simplify Equation: First, distribute the slope 73\frac{7}{3} across the (x−2)(x - 2) term: y−4=(73)x−(73)∗2y - 4 = \left(\frac{7}{3}\right)x - \left(\frac{7}{3}\right)*2. Simplifying further, we get y−4=(73)x−143y - 4 = \left(\frac{7}{3}\right)x - \frac{14}{3}.
  5. Add Constant Terms: Next, we add 44 to both sides of the equation to solve for yy: y=73x−143+4y = \frac{7}{3}x - \frac{14}{3} + 4. To combine like terms, we need to express 44 as a fraction with a denominator of 33, which is 123\frac{12}{3}. So the equation becomes y=73x−143+123y = \frac{7}{3}x - \frac{14}{3} + \frac{12}{3}.
  6. Final Equation: Combining the constant terms, we get y=73x−23y = \frac{7}{3}x - \frac{2}{3}. This is the equation of line dd in slope-intercept form.

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