Q. It is given that the constant term in the expansion of (2+x1)2(1−3x)n is 67 , where n is a positive integer. Find the value of n.
Identify Terms Form: Identify the general form of the terms in the expansion of (2+1/x)2 and (1−3x)n. For (2+1/x)2, expand using binomial theorem: (2+1/x)2=4+4/x+1/x2. For (1−3x)n, use binomial theorem: (1−3x)n=Σ(from k=0 to n)[(kn)⋅1(n−k)⋅(−3x)k].