Q. In the figure below AD is tangent to circle O at D, AD=15, and BC=16. Find AB
Identify Theorem: Identify the relevant theorem for solving the problem. Since AD is tangent to the circle at D, and we know AD=15, we can use the Pythagorean theorem in triangle ADB, assuming AB is the hypotenuse.
Set Up Pythagorean Theorem: Set up the Pythagorean theorem for triangle ADB. Let AB = x, then:AD2+BD2=AB2152+BD2=x2We need to find BD, which is the radius of the circle.
Use Pythagorean Theorem: Since BC = 16 and it is a chord, the perpendicular from the center O to BC (let's call it OM) bisects BC. So, BM = MC = 8. Using the Pythagorean theorem in triangle OMB (right triangle), where OM is the radius:OM2+BM2=OB2r2+82=r2This equation is incorrect, as it implies that 8^2 = 0.
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