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In the figure below ADAD is tangent to circle OO at DD, AD=15AD=15, and BC=16BC=16. Find ABAB

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Q. In the figure below ADAD is tangent to circle OO at DD, AD=15AD=15, and BC=16BC=16. Find ABAB
  1. Identify Theorem: Identify the relevant theorem for solving the problem. Since ADAD is tangent to the circle at DD, and we know AD=15AD = 15, we can use the Pythagorean theorem in triangle ADBADB, assuming ABAB is the hypotenuse.
  2. Set Up Pythagorean Theorem: Set up the Pythagorean theorem for triangle ADB. Let AB = x, then:\newlineAD2+BD2=AB2 AD^2 + BD^2 = AB^2 \newline152+BD2=x2 15^2 + BD^2 = x^2 \newlineWe need to find BD, which is the radius of the circle.
  3. Use Pythagorean Theorem: Since BC = 1616 and it is a chord, the perpendicular from the center O to BC (let's call it OM) bisects BC. So, BM = MC = 88. Using the Pythagorean theorem in triangle OMB (right triangle), where OM is the radius:\newlineOM2+BM2=OB2 OM^2 + BM^2 = OB^2 \newliner2+82=r2 r^2 + 8^2 = r^2 \newlineThis equation is incorrect, as it implies that 88^22 = 00.

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