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In a lab experiment, 6300 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 8 hours. How many bacteria would there be after 19 hours, to the nearest whole number?
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In a lab experiment, 63006300 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 88 hours. How many bacteria would there be after 1919 hours, to the nearest whole number?\newlineAnswer:

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Q. In a lab experiment, 63006300 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 88 hours. How many bacteria would there be after 1919 hours, to the nearest whole number?\newlineAnswer:
  1. Calculate Doubling Periods: Determine the number of times the bacteria population will double in 1919 hours.\newlineSince the bacteria double every 88 hours, we divide the total time by the doubling period.\newline1919 hours ÷\div 88 hours per doubling period = 2.3752.375 doubling periods.
  2. Calculate Bacteria After Doubling Periods: Since bacteria can only double a whole number of times, we need to consider only the whole number part of the doubling periods for the calculation.\newlineThe number of complete doubling periods in 1919 hours is 22 (since we cannot have a fraction of a doubling period).
  3. Calculate Remaining Time: Calculate the number of bacteria after the complete doubling periods.\newlineThe population doubles 22 times, so we multiply the initial number of bacteria by 22 raised to the power of the number of doublings.\newline63006300 bacteria ×(22)=6300×4=25200\times (2^2) = 6300 \times 4 = 25200 bacteria after 1616 hours (22 complete doubling periods).
  4. Calculate Growth During Remaining Time: Determine the remaining time after the last complete doubling period. 1919 hours - 1616 hours (22 complete doubling periods of 88 hours each) = 33 hours remaining.
  5. Apply Growth for Partial Period: Calculate the growth of bacteria during the remaining 33 hours.\newlineSince the bacteria double every 88 hours, we can find the fraction of doubling that occurs in 33 hours by dividing 33 by 88.\newline33 hours ÷\div 88 hours per doubling period = 0.3750.375 of a doubling period.
  6. Round Bacteria Count: Apply the growth for the partial doubling period to the bacteria count after 1616 hours.\newlineWe need to multiply the number of bacteria after 1616 hours by 22 raised to the power of 0.3750.375 to find the number of bacteria after the remaining 33 hours.\newline2520025200 bacteria ×(20.375)25200×1.33333600\times (2^{0.375}) \approx 25200 \times 1.333 \approx 33600 bacteria after 1919 hours.
  7. Round Bacteria Count: Apply the growth for the partial doubling period to the bacteria count after 1616 hours.\newlineWe need to multiply the number of bacteria after 1616 hours by 22 raised to the power of 0.3750.375 to find the number of bacteria after the remaining 33 hours.\newline2520025200 bacteria ×(20.375)25200×1.33333600\times (2^{0.375}) \approx 25200 \times 1.333 \approx 33600 bacteria after 1919 hours.Round the result to the nearest whole number, as bacteria count cannot be a fraction.\newlineThe number of bacteria after 1919 hours, rounded to the nearest whole number, is approximately 3360033600.

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