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If 
y=5y^(3)+2x^(3) then find 
(dy)/(dx) in terms of 
x and 
y.
Answer: 
(dy)/(dx)=

If y=5y3+2x3 y=5 y^{3}+2 x^{3} then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. If y=5y3+2x3 y=5 y^{3}+2 x^{3} then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Differentiation Process: To find the derivative of yy with respect to xx, we need to differentiate both sides of the equation with respect to xx. The equation is y=5y3+2x3y = 5y^3 + 2x^3.
  2. Derivative of yy: Differentiate the left side of the equation with respect to xx. The derivative of yy with respect to xx is simply dydx\frac{dy}{dx}.
  3. Derivative of Right Side: Differentiate the right side of the equation with respect to xx. The term 5y35y^3 is treated as a function of xx, so we apply the chain rule. The derivative of 5y35y^3 with respect to xx is 15y2dydx15y^2 \cdot \frac{dy}{dx}. The derivative of 2x32x^3 with respect to xx is 6x26x^2.
  4. Combining Derivatives: Combine the derivatives to form the equation: dydx=15y2(dydx)+6x2\frac{dy}{dx} = 15y^2 \cdot \left(\frac{dy}{dx}\right) + 6x^2.
  5. Isolating dydx\frac{dy}{dx}: To solve for dydx\frac{dy}{dx}, we need to move all terms involving dydx\frac{dy}{dx} to one side of the equation. Subtract 15y2×dydx15y^2 \times \frac{dy}{dx} from both sides to get: dydx15y2×dydx=6x2\frac{dy}{dx} - 15y^2 \times \frac{dy}{dx} = 6x^2.
  6. Factoring out dydx\frac{dy}{dx}: Factor out dydx\frac{dy}{dx} on the left side of the equation to get: dydx×(115y2)=6x2\frac{dy}{dx} \times (1 - 15y^2) = 6x^2.
  7. Final Derivative Solution: Divide both sides of the equation by (115y2)(1 - 15y^2) to solve for dydx\frac{dy}{dx}. This gives us: dydx=6x2(115y2)\frac{dy}{dx} = \frac{6x^2}{(1 - 15y^2)}.

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