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If 
x^(2)-2xy+y^(2)=25, then 
x-y=
(a) 25
(b) -5
(c) 5
(d) 
+-5

Galaxy Note10 Lite

33) If x22xy+y2=25 x^{2}-2 x y+y^{2}=25 , then xy= x-y= \newline(a) 2525\newline(b) 5-5\newline(c) 55\newline(d) ±5 \pm 5 \newlineGalaxy Note1010 Lite

Full solution

Q. 33) If x22xy+y2=25 x^{2}-2 x y+y^{2}=25 , then xy= x-y= \newline(a) 2525\newline(b) 5-5\newline(c) 55\newline(d) ±5 \pm 5 \newlineGalaxy Note1010 Lite
  1. Recognize pattern in equation: Recognize the pattern in the equation x22xy+y2x^2 - 2xy + y^2. The given equation resembles the formula for the square of a binomial (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2. Here, a=xa = x and b=yb = y, so the equation can be rewritten as (xy)2=25(x - y)^2 = 25.
  2. Rewrite equation as square: Take the square root of both sides of the equation to solve for xyx - y.\newlineSince (xy)2=25(x - y)^2 = 25, we have xy=±25x - y = \pm\sqrt{25}.
  3. Take square root to solve: Calculate the square root of 2525.\newlineThe square root of 2525 is 55, so xy=±5x - y = \pm 5.

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