Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

If sin6y=cos9y\sin 6y = \cos 9y, then yy is equal to\newline(11) 1.51.5\newline(22) 3636\newline(33) 66\newline(44) 5454

Full solution

Q. If sin6y=cos9y\sin 6y = \cos 9y, then yy is equal to\newline(11) 1.51.5\newline(22) 3636\newline(33) 66\newline(44) 5454
  1. Set up equation: We know that the sine and cosine functions are co-functions, meaning that sin(θ)=cos(90°θ)\sin(\theta) = \cos(90° - \theta) for angles measured in degrees. Therefore, we can set up the equation sin(6y)=cos(9y)\sin(6y) = \cos(9y) as sin(6y)=cos(90°6y)\sin(6y) = \cos(90° - 6y).
  2. Equate angles: Now we can equate the angles inside the sine and cosine functions: 6y=90°9y6y = 90° - 9y.
  3. Add and solve: To solve for yy, we add 9y9y to both sides of the equation: 6y+9y=90°6y + 9y = 90°.
  4. Combine terms: Combining like terms, we get 15y=9015y = 90^\circ.
  5. Divide and solve: Now we divide both sides by 1515 to solve for yy: y=90°15y = \frac{90°}{15}.
  6. Calculate final value: Calculating the division, we find y=6y = 6^\circ.

More problems from Estimate products of fractions and whole numbers