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If h(w)=19w238w2h(w) = 19w^2 - 38w - 2, use synthetic division to find h(1)h(1).

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Q. If h(w)=19w238w2h(w) = 19w^2 - 38w - 2, use synthetic division to find h(1)h(1).
  1. Set up synthetic division: First, set up the synthetic division with 11 as the root we're testing and the coefficients of h(w)h(w) in descending order of ww.
  2. Bring down first coefficient: The synthetic division setup looks like this:\newline1193821 | 19 -38 -2\newlineNow, bring down the 1919 to the bottom row.
  3. Multiply and write result: Multiply 11 by 1919 and write the result under the next coefficient:\newline1193821 \,|\, 19 \,-38 \,-2\newline\,\,|\,\underline{\quad\quad\quad\quad}\newline\,\,|\, 1919 \,\, 1919
  4. Add numbers in second column: Add the numbers in the second column:\newline38+19=19-38 + 19 = -19\newlineWrite this sum in the bottom row.\newline1191 | 19 38-38 2-2\newline |_______\newline | 1919 19-19
  5. Multiply and write result: Multiply 11 by 19-19 and write the result under the next coefficient:\newline1193821 \,|\, 19 \,-38 \,-2\newline\phantom{1 \,|\,}_______19\newline11919191 \,|\, 19 \,-19 \,-19
  6. Add numbers in third column: Add the numbers in the third column:\newline2+(19)=21-2 + (-19) = -21\newlineWrite this sum in the bottom row.\newline1193821 | 19 -38 -2\newline |_______191919 -19\newline | 19192119 -19 -21
  7. Find remainder: The number in the bottom right is the remainder, which represents h(1)h(1).

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