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If h(t)=22t239t11h(t) = 22t^2 - 39t - 11, use synthetic division to find h(2)h(2).

Full solution

Q. If h(t)=22t239t11h(t) = 22t^2 - 39t - 11, use synthetic division to find h(2)h(2).
  1. Write coefficients and value: To use synthetic division, we first write down the coefficients of the polynomial h(t)h(t) and the value for tt we want to evaluate, which is 22.
  2. Set up synthetic division: Set up synthetic division by writing 22 on the left side and the coefficients 2222, 39-39, and 11-11 on the right side.
  3. Bring down first coefficient: Bring down the first coefficient, 2222, to the bottom row.
  4. Multiply and write result: Multiply 22 by 2222 and write the result, 4444, under the next coefficient, 39-39.
  5. Add and write result: Add 39-39 and 4444 to get 55. Write this number under the line.
  6. Multiply and write result: Multiply 22 by 55 and write the result, 1010, under the last coefficient, 11-11.
  7. Add and find remainder: Add 11-11 and 1010 to get 1-1. This is the remainder and also the value of h(2)h(2).

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