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If 3(r+300)=63(r+300)=6 then what is the value of r+300−2r+300-2?

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Full solution

Q. If 3(r+300)=63(r+300)=6 then what is the value of r+300−2r+300-2?
  1. Solve for r+300r+300: Solve for r+300r+300 from the equation 3(r+300)=63(r+300) = 6.\newline3(r+300)=63(r+300) = 6\newliner+300=63r+300 = \frac{6}{3}\newliner+300=2r+300 = 2

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