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If 153=2(z+z)n153=2(z+z)n, then what is the value of 2n(2z)1932n(2z)-193?

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Q. If 153=2(z+z)n153=2(z+z)n, then what is the value of 2n(2z)1932n(2z)-193?
  1. Simplify the equation: First, let's simplify the given equation 153=2(z+z)n153 = 2(z + z)n. Since 2(z+z)2(z + z) is the same as 4z4z, we can rewrite the equation as 153=4zn153 = 4zn.
  2. Solve for n: Now, we need to solve for n. To do this, we divide both sides of the equation by 4z4z to isolate nn.\newlineSo, n=1534zn = \frac{153}{4z}.
  3. Substitute nn into expression: Next, we need to find the value of 2n(2z)1932n(2z) - 193. We already have nn expressed in terms of zz, so we can substitute 1534z\frac{153}{4z} for nn in the expression.\newlineThis gives us 2(1534z)(2z)1932\left(\frac{153}{4z}\right)(2z) - 193.
  4. Simplify the expression: We can simplify the expression by multiplying 2(2z)2(2z) by 153/(4z)153 / (4z). The 2z2z in the numerator and the zz in the denominator will cancel out one zz, and 2×22 \times 2 gives us 44, which cancels with the 44 in the denominator. This simplifies to 2×1531932 \times 153 - 193.
  5. Calculate 2×1532 \times 153: Now, we calculate 2×1532 \times 153, which is 306306. So, we have 306193306 - 193.
  6. Find the final value: Finally, we subtract 193193 from 306306 to find the value of the expression.\newline306193306 - 193 equals 113113.

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