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Identify the part of the circle given the equation. 8. (x-2)^(2)+(y+13)^(2)=150 Center : ( 2 -13 radius : ◻ ◻

Identify the part of the circle given the equation.\newline88. (x−2)2+(y+13)2=150 (x-2)^{2}+(y+13)^{2}=150 \newlineCenter : ( 22\newline−13 -13 \newlineradius : □ \square \newline□ \square

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Q. Identify the part of the circle given the equation.\newline88. (x−2)2+(y+13)2=150 (x-2)^{2}+(y+13)^{2}=150 \newlineCenter : ( 22\newline−13 -13 \newlineradius : □ \square \newline□ \square
  1. Recognize standard form: Recognize the standard form of a circle's equation, which is (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2, where (h,k)(h, k) is the center and rr is the radius.
  2. Compare with standard form: Compare the given equation (x−2)2+(y+13)2=150(x-2)^2 + (y+13)^2 = 150 with the standard form. Here, h=2h = 2 and k=−13k = -13, so the center is (2,−13)(2, -13).
  3. Calculate radius: The radius rr is the square root of the right side of the equation. Calculate r=150r = \sqrt{150}. Simplifying, r=56r = 5\sqrt{6}.

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