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How many solutions does the system have?\newline{x+y=3 5x+5y=15\begin{cases} x+y=3 \\ \ 5x+5y=15 \end{cases}

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Q. How many solutions does the system have?\newline{x+y=3 5x+5y=15\begin{cases} x+y=3 \\ \ 5x+5y=15 \end{cases}
  1. Write Equations: First, let's write down the system of equations to analyze it.{x+y=3 5x+5y=15\begin{cases} x + y = 3 \ 5x + 5y = 15 \end{cases}
  2. Observe Equation Relationship: Next, we observe that the second equation is simply the first equation multiplied by 55. This means that the two equations are actually the same line represented in different forms.
  3. Identify Infinite Solutions: Since both equations represent the same line, every point on the line is a solution to both equations. Therefore, the system does not have a unique solution; instead, it has infinitely many solutions.
  4. Confirm Observation: To confirm our observation, we can divide the second equation by 55 to see if it simplifies to the first equation.\newline5x+5y5=155\frac{5x + 5y}{5} = \frac{15}{5}\newlinex+y=3x + y = 3\newlineThis confirms that the second equation is indeed a multiple of the first.

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