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Select two answer choices.\newline(a) The point (−4,0)(-4,0) is on the line.\newline(b) The point (0,−4)(0,-4) is on the line.\newline(c) The point (36,28)(36,28) is on the line.\newline(d) The graph represents the equation 2x−3y=−122x-3y=-12.\newline(e) The graph represents the equation 2x+3y=−122x+3y=-12.

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Q. Select two answer choices.\newline(a) The point (−4,0)(-4,0) is on the line.\newline(b) The point (0,−4)(0,-4) is on the line.\newline(c) The point (36,28)(36,28) is on the line.\newline(d) The graph represents the equation 2x−3y=−122x-3y=-12.\newline(e) The graph represents the equation 2x+3y=−122x+3y=-12.
  1. Check Point (−4,0)(-4,0): Check if the point (−4,0)(-4,0) is on the line represented by the equation 2x−3y=−122x-3y=-12. Substitute x=−4x = -4 and y=0y = 0 into the equation:\newline2(−4)−3(0)=−8≠−122(-4) - 3(0) = -8 \neq -12.
  2. Check Point 0,−40,-4: Check if the point 0,−40,-4 is on the line represented by the equation 2x−3y=−122x-3y=-12. Substitute x=0x = 0 and y=−4y = -4 into the equation:2(0)−3(−4)=12≠−122(0) - 3(-4) = 12 \neq -12.
  3. Check Point 36,2836,28: Check if the point 36,2836,28 is on the line represented by the equation 2x−3y=−122x-3y=-12. Substitute x=36x = 36 and y=28y = 28 into the equation:2(36)−3(28)=72−84=−122(36) - 3(28) = 72 - 84 = -12.
  4. Verify Equation Match Graph: Verify the equation 2x−3y=−122x-3y=-12 by checking if it matches the graph. Since the point (36,28)(36,28) satisfies this equation, it likely represents the line on the graph.
  5. Verify Equation Does Not Match Graph: Verify the equation 2x+3y=−122x+3y=-12 by checking if it matches the graph. Substitute a known point from the previous steps, e.g., (36,28)(36,28):\newline2(36)+3(28)=72+84=156≠−122(36) + 3(28) = 72 + 84 = 156 \neq -12.

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