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What is the amplitude of y=5sin(4x-2)-3 ? units

What is the amplitude of y=5sin⁡(4x−2)−3 y=5 \sin (4 x-2)-3 ?\newlineunits

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Q. What is the amplitude of y=5sin⁡(4x−2)−3 y=5 \sin (4 x-2)-3 ?\newlineunits
  1. Identify Amplitude: Identify the amplitude from the standard form of the sine function.\newlineThe standard form of a sine function is y=A⋅sin⁡(Bx−C)+Dy = A \cdot \sin(Bx - C) + D, where AA is the amplitude.\newlineIn the given function y=5sin⁡(4x−2)−3y = 5\sin(4x - 2) - 3, the coefficient of sin⁡(4x−2)\sin(4x - 2) is 55.\newlineTherefore, the amplitude is the absolute value of 55.
  2. Confirm Positive Amplitude: Confirm that the amplitude is a positive value.\newlineAmplitude is always a non-negative number because it represents the maximum displacement from the midline of the wave.\newlineSince 55 is already a positive number, we can confirm that the amplitude is indeed 55.

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