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h(x)=2x2+11x+15h(x)= 2x^{2} +11x +15

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Q. h(x)=2x2+11x+15h(x)= 2x^{2} +11x +15
  1. Factor or Use Quadratic Formula: To find the roots of the quadratic function h(x)=2x2+11x+15h(x) = 2x^2 + 11x + 15, we need to solve the equation 2x2+11x+15=02x^2 + 11x + 15 = 0. We can attempt to factor the quadratic, or use the quadratic formula to find the roots.
  2. Quadratic Formula Coefficients: The quadratic formula is given by x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0. For our function h(x)h(x), a=2a = 2, b=11b = 11, and c=15c = 15.
  3. Calculate Discriminant: First, we calculate the discriminant, which is b24acb^2 - 4ac. For our equation, the discriminant is 1124(2)(15)11^2 - 4(2)(15).
  4. Calculate Discriminant Result: Calculating the discriminant: 1124(2)(15)=121120=111^2 - 4(2)(15) = 121 - 120 = 1.
  5. Use Quadratic Formula: Since the discriminant is positive, we will have two real and distinct roots. Now we can use the quadratic formula to find the roots.
  6. Substitute Values: Substitute the values of aa, bb, and cc into the quadratic formula: x=11±12×2x = \frac{-11 \pm \sqrt{1}}{2 \times 2}.
  7. Simplify Expression: Simplify the expression: x=11±14x = \frac{{-11 \pm 1}}{{4}}.
  8. Find Two Roots: Now, we find the two roots by solving for xx with both the positive and negative values of the square root of the discriminant.
  9. Positive Square Root: For the positive square root: x=(11+1)/4=10/4=2.5x = (-11 + 1) / 4 = -10 / 4 = -2.5.
  10. Negative Square Root: For the negative square root: x=(111)/4=12/4=3x = ( -11 - 1 ) / 4 = -12 / 4 = -3.

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