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Given 
y=3cot^(3)(x), find 
(dy)/(dx).
Answer: 
(dy)/(dx)=

Given y=3cot3(x) y=3 \cot ^{3}(x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. Given y=3cot3(x) y=3 \cot ^{3}(x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Identify Function: Identify the function to differentiate.\newlineWe are given the function y=3cot3(x)y = 3\cot^{3}(x), which means yy is equal to three times the cube of the cotangent of xx.
  2. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is f(u)=3u3f(u) = 3u^3 and the inner function is u(x)=cot(x)u(x) = \cot(x). We need to find the derivative of both functions.
  3. Differentiate Outer Function: Differentiate the outer function f(u)=3u3f(u) = 3u^3 with respect to uu. The derivative of f(u)f(u) with respect to uu is f(u)=3×3u31=9u2f'(u) = 3 \times 3u^{3-1} = 9u^2.
  4. Differentiate Inner Function: Differentiate the inner function u(x)=cot(x)u(x) = \cot(x) with respect to xx. The derivative of cot(x)\cot(x) with respect to xx is csc2(x)-\csc^2(x), where csc(x)\csc(x) is the cosecant of xx.
  5. Apply Chain Rule with Derivatives: Apply the chain rule using the derivatives from steps 33 and 44.\newlinedydx=f(u)dudx=9u2(csc2(x))=9cot2(x)(csc2(x))\frac{dy}{dx} = f'(u) \cdot \frac{du}{dx} = 9u^2 \cdot (-\csc^2(x)) = 9\cot^2(x) \cdot (-\csc^2(x)).
  6. Substitute Back to x: Substitute uu back with cot(x)\cot(x) to get the derivative in terms of xx.dydx=9cot2(x)(csc2(x))=9cot2(x)csc2(x)\frac{dy}{dx} = 9\cot^2(x) \cdot (-\csc^2(x)) = -9\cot^2(x)\csc^2(x).
  7. Check for Errors: Check for any mathematical errors in the differentiation process.\newlineNo mathematical errors were made in the differentiation process.

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