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Given 
y=3cot(2x), find 
(dy)/(dx).
Answer: 
(dy)/(dx)=
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Given y=3cot(2x) y=3 \cot (2 x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}= \newlineSubmit Answer

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Q. Given y=3cot(2x) y=3 \cot (2 x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}= \newlineSubmit Answer
  1. Identify Function and Rules: Identify the function to differentiate and the rules that will be applied. The function is y=3cot(2x)y = 3\cot(2x), and we will use the chain rule and the derivative of cotangent.
  2. Recall Cotangent Derivative: Recall the derivative of cotangent. The derivative of cot(x)\cot(x) with respect to xx is csc2(x)-\csc^2(x), where csc\csc is the cosecant function.
  3. Apply Chain Rule: Apply the chain rule. The chain rule states that the derivative of a composite function f(g(x))f(g(x)) is f(g(x))g(x)f'(g(x))g'(x). Here, f(x)=3cot(x)f(x) = 3\cot(x) and g(x)=2xg(x) = 2x. We need to find the derivative of ff with respect to gg and then multiply by the derivative of gg with respect to xx.
  4. Differentiate Composite Function: Differentiate f(g(x))=3cot(g(x))f(g(x)) = 3\cot(g(x)) with respect to gg. The derivative is 3csc2(g(x))-3\csc^2(g(x)) because the derivative of cotangent is csc2(x)-\csc^2(x), and we multiply by the constant 33.
  5. Differentiate Linear Function: Differentiate g(x)=2xg(x) = 2x with respect to xx. The derivative is 22 because the derivative of xx with respect to xx is 11, and we multiply by the constant 22.
  6. Combine Derivatives: Combine the derivatives using the chain rule. Multiply the derivative of ff with respect to gg by the derivative of gg with respect to xx to get the derivative of yy with respect to xx. This gives us dydx=3csc2(2x)×2\frac{dy}{dx} = -3\csc^2(2x) \times 2.
  7. Simplify Final Result: Simplify the expression. Multiply 3-3 by 22 to get 6-6. The final derivative is dydx=6csc2(2x)\frac{dy}{dx} = -6\csc^2(2x).

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