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Given 
y=2cot^(3)(x), find 
(dy)/(dx).
Answer: 
(dy)/(dx)=

Given y=2cot3(x) y=2 \cot ^{3}(x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. Given y=2cot3(x) y=2 \cot ^{3}(x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Identify Function: Identify the function to differentiate. The function given is y=2cot3(x)y = 2\cot^{3}(x), which means y=2[cot(x)]3y = 2[\cot(x)]^3.
  2. Apply Chain Rule: Recognize that to differentiate yy with respect to xx, we need to apply the chain rule because we have a function raised to a power. The chain rule states that the derivative of a composite function f(g(x))f(g(x)) is f(g(x))g(x)f'(g(x))g'(x).
  3. Differentiate Outer Function: Differentiate the outer function first, keeping the inner function the same. The outer function is u3u^3 where u=cot(x)u = \cot(x), and its derivative with respect to uu is 3u23u^2. So, the derivative of the outer function with respect to cot(x)\cot(x) is 3[cot(x)]23[\cot(x)]^2.
  4. Differentiate Inner Function: Now, differentiate the inner function, which is cot(x)\cot(x). The derivative of cot(x)\cot(x) with respect to xx is csc2(x)-\csc^2(x), where csc(x)\csc(x) is the cosecant function.
  5. Apply Chain Rule Again: Apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us the derivative of yy with respect to xx: dydx=3[cot(x)]2×(csc2(x))\frac{dy}{dx} = 3[\cot(x)]^2 \times (-\csc^2(x)).
  6. Multiply by Constant Factor: Finally, multiply the result by the constant factor from the original function, which is 22. This gives us dydx=2×3[cot(x)]2×(csc2(x))\frac{dy}{dx} = 2 \times 3[\cot(x)]^2 \times (-\csc^2(x)).
  7. Simplify and Final Answer: Simplify the expression by combining constants and writing the final answer. The constants 22 and 33 can be multiplied together to give 66, and the negative sign remains. So, the final answer is dydx=6[cot(x)]2csc2(x)\frac{dy}{dx} = -6[\cot(x)]^2 \cdot \csc^2(x).

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