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Given that 
y=3u^(2)+4, find 
(d)/(du)(2u^(5)-4sin y) in terms of only 
u.
Answer:

Given that y=3u2+4 y=3 u^{2}+4 , find ddu(2u54siny) \frac{d}{d u}\left(2 u^{5}-4 \sin y\right) in terms of only u u .\newlineAnswer:

Full solution

Q. Given that y=3u2+4 y=3 u^{2}+4 , find ddu(2u54siny) \frac{d}{d u}\left(2 u^{5}-4 \sin y\right) in terms of only u u .\newlineAnswer:
  1. Identify Function: Identify the function that needs to be differentiated and the function yy in terms of uu.
  2. Differentiate Power Rule: Differentiate the function 2u52u^{5} with respect to uu using the power rule, which states that ddu[un]=nu(n1)\frac{d}{du}[u^n] = n\cdot u^{(n-1)}.\newlineCalculation: ddu[2u5]=25u(51)=10u4\frac{d}{du}[2u^{5}] = 2\cdot 5\cdot u^{(5-1)} = 10u^{4}
  3. Apply Chain Rule: Recognize that yy is a function of uu, so when differentiating 4sin(y)-4\sin(y) with respect to uu, we need to use the chain rule. The chain rule states that ddu[f(g(u))]=f(g(u))g(u)\frac{d}{du}[f(g(u))] = f'(g(u)) \cdot g'(u).
  4. Differentiate y=3u2+4y=3u^{2}+4: Differentiate y=3u2+4y=3u^{2}+4 with respect to uu to find dydu\frac{dy}{du}.\newlineCalculation: dydu=ddu[3u2+4]=6u\frac{dy}{du} = \frac{d}{du}[3u^{2}+4] = 6u
  5. Apply Chain Rule: Apply the chain rule to differentiate 4sin(y)-4\sin(y) with respect to uu.\newlineCalculation: ddu[4sin(y)]=4cos(y)dydu=4cos(y)6u=24ucos(y)\frac{d}{du}[-4\sin(y)] = -4\cos(y) \cdot \frac{dy}{du} = -4\cos(y) \cdot 6u = -24u\cos(y)
  6. Substitute y=3u2+4y=3u^{2}+4: Substitute y=3u2+4y=3u^{2}+4 into the expression 24ucos(y)-24u\cos(y) to express it in terms of uu.\newlineCalculation: 24ucos(3u2+4)-24u\cos(3u^{2}+4)
  7. Combine Derivatives: Combine the derivatives of 2u52u^{5} and 4sin(y)-4\sin(y) to get the final derivative in terms of uu.\newlineCalculation: ddu[2u54sin(y)]=10u424ucos(3u2+4)\frac{d}{du}[2u^{5}-4\sin(y)] = 10u^{4} - 24u\cos(3u^{2}+4)

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