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For the rotation 1140^(@), find the coterminal angle from 0^(@) <= theta < 360^(@), the quadrant, and the reference angle. The coterminal angle is ◻^(@), which lies in Quadrant ◻, with a reference angle of ◻^(@).

For the rotation 1140∘ 1140^{\circ} , find the coterminal angle from 0∘≤θ<360∘ 0^{\circ} \leq \theta<360^{\circ} , the quadrant, and the reference angle.\newlineThe coterminal angle is □∘ \square^{\circ} , which lies in Quadrant □ \square, with a reference angle of □∘ \square^{\circ} .

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Q. For the rotation 1140∘ 1140^{\circ} , find the coterminal angle from 0∘≤θ<360∘ 0^{\circ} \leq \theta<360^{\circ} , the quadrant, and the reference angle.\newlineThe coterminal angle is □∘ \square^{\circ} , which lies in Quadrant □ \square, with a reference angle of □∘ \square^{\circ} .
  1. Determine Quadrant: Now we determine the quadrant for the 6060-degree angle.\newlineSince 6060 degrees is between 00 and 9090 degrees, it lies in Quadrant I.
  2. Find Reference Angle: Next, we find the reference angle for the 6060-degree angle.\newlineThe reference angle in Quadrant I is the angle itself.\newlineReference angle = 6060 degrees.

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