Q. For the polynomial below, 1 is a zero.g(x)=x3−7x2+12x−6Express g(x) as a product of linear factors.g(x)=
Identify Zero and Factor: Since 1 is a zero of the polynomial g(x), we know that (x−1) is a factor of g(x). To find the other factors, we can perform polynomial division or use synthetic division to divide g(x) by (x−1).
Perform Synthetic Division: Let's use synthetic division to divide g(x) by (x−1). We set up the synthetic division as follows:\begin{array}{r|rrrr}
1 & 1 & -7 & 12 & -6 \
& \underline{+1} & \underline{-6} & \underline{6} \
& 1 & -6 & 6 & 0
\end{array}The remainder is 0, which confirms that 1 is indeed a zero of g(x). The quotient from the synthetic division is x2−6x+6.
Factor Quadratic Polynomial: Now we need to factor the quadratic polynomial x2−6x+6. We look for two numbers that multiply to 6 and add up to −6. The numbers −3 and −2 satisfy these conditions.
Express as Linear Factors: We can now express the quadratic polynomial as a product of two linear factors: (x−3)(x−2).
Express as Linear Factors: We can now express the quadratic polynomial as a product of two linear factors: (x−3)(x−2).Combining the linear factor we found from the zero of the polynomial with the factors of the quadratic, we can express g(x) as a product of linear factors: g(x)=(x−1)(x−3)(x−2).
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