Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

For the polynomial below, 11 is a zero.\newlineg(x)=x37x2+12x6g(x)=x^{3}-7x^{2}+12x-6\newlineExpress \newlineg(x)g(x) as a product of linear factors.\newlineg(x)=g(x)=

Full solution

Q. For the polynomial below, 11 is a zero.\newlineg(x)=x37x2+12x6g(x)=x^{3}-7x^{2}+12x-6\newlineExpress \newlineg(x)g(x) as a product of linear factors.\newlineg(x)=g(x)=
  1. Identify Zero and Factor: Since 11 is a zero of the polynomial g(x)g(x), we know that (x1)(x - 1) is a factor of g(x)g(x). To find the other factors, we can perform polynomial division or use synthetic division to divide g(x)g(x) by (x1)(x - 1).
  2. Perform Synthetic Division: Let's use synthetic division to divide g(x)g(x) by (x1)(x - 1). We set up the synthetic division as follows:\newline\begin{array}{r|rrrr} 1 & 1 & -7 & 12 & -6 \ & \underline{+1} & \underline{-6} & \underline{6} \ & 1 & -6 & 6 & 0 \end{array}\newlineThe remainder is 00, which confirms that 11 is indeed a zero of g(x)g(x). The quotient from the synthetic division is x26x+6x^2 - 6x + 6.
  3. Factor Quadratic Polynomial: Now we need to factor the quadratic polynomial x26x+6x^2 - 6x + 6. We look for two numbers that multiply to 66 and add up to 6-6. The numbers 3-3 and 2-2 satisfy these conditions.
  4. Express as Linear Factors: We can now express the quadratic polynomial as a product of two linear factors: (x3)(x2)(x - 3)(x - 2).
  5. Express as Linear Factors: We can now express the quadratic polynomial as a product of two linear factors: (x3)(x2)(x - 3)(x - 2).Combining the linear factor we found from the zero of the polynomial with the factors of the quadratic, we can express g(x)g(x) as a product of linear factors: g(x)=(x1)(x3)(x2)g(x) = (x - 1)(x - 3)(x - 2).

More problems from Find the roots of factored polynomials