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For the following equation, evaluate 
(dy)/(dx) when 
x=2.

y=3x^(3)+4
Answer:

For the following equation, evaluate dydx \frac{d y}{d x} when x=2 x=2 .\newliney=3x3+4 y=3 x^{3}+4 \newlineAnswer:

Full solution

Q. For the following equation, evaluate dydx \frac{d y}{d x} when x=2 x=2 .\newliney=3x3+4 y=3 x^{3}+4 \newlineAnswer:
  1. Find Derivative: To find the derivative of yy with respect to xx, we need to differentiate the function y=3x3+4y=3x^{3}+4. Differentiate each term separately: The derivative of 3x33x^{3} with respect to xx is 3×3x(31)=9x23 \times 3x^{(3-1)} = 9x^{2}. The derivative of a constant, like 44, is 00. So, dydx=9x2+0\frac{dy}{dx} = 9x^{2} + 0, which simplifies to dydx=9x2\frac{dy}{dx} = 9x^{2}.
  2. Differentiate Terms: Now we need to evaluate the derivative at x=2x=2. Substitute x=2x=2 into the derivative to get dydx=9(2)2\frac{dy}{dx} = 9\cdot(2)^2. Calculate the value: 9(2)2=94=369\cdot(2)^2 = 9\cdot4 = 36.

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