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Find the yy-intercept of the parabola y=x2+5x+10y = x^2 + 5x + 10. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2+5x+10y = x^2 + 5x + 10. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Evaluate at x=0x = 0: To find the y-intercept of the parabola, we need to evaluate the equation y=x2+5x+10y = x^2 + 5x + 10 at x=0x = 0, because the y-intercept occurs where the graph of the equation crosses the y-axis, and the x-coordinate is always 00 at the y-axis.
  2. Substitute x=0x = 0: Substitute x=0x = 0 into the equation y=x2+5x+10y = x^2 + 5x + 10 to find the y-intercept.\newliney=(0)2+5(0)+10y = (0)^2 + 5(0) + 10\newliney=0+0+10y = 0 + 0 + 10\newliney=10y = 10
  3. Find y-intercept: The y-intercept of the parabola y=x2+5x+10y = x^2 + 5x + 10 is the point (0,10)(0, 10).

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