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Find the yy-intercept of the parabola y=x2+5y = x^2 + 5. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Full solution

Q. Find the yy-intercept of the parabola y=x2+5y = x^2 + 5. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Find y-intercept: To find the y-intercept of the parabola, we need to determine the value of yy when x=0x = 0.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the equation y=x2+5y = x^2 + 5.\newliney=(0)2+5y = (0)^2 + 5\newliney=0+5y = 0 + 5\newliney=5y = 5
  3. Calculate yy: The yy-intercept of the parabola is the point (0,y)(0, y) where yy is the value we just calculated.\newlineTherefore, the yy-intercept is (0,5)(0, 5).

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