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Find the yy-intercept of the parabola y=x2+4x−4y = x^2 + 4x - 4. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2+4x−4y = x^2 + 4x - 4. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Evaluate at x=0x = 0: To find the y-intercept of the parabola, we need to evaluate the equation at x=0x = 0, because the y-intercept is the point where the graph of the equation crosses the y-axis, and at this point, the value of xx is always 00.
  2. Substitute xx into equation: Substitute x=0x = 0 into the equation y=x2+4x−4y = x^2 + 4x − 4.\newliney=(0)2+4(0)−4y = (0)^2 + 4(0) − 4\newliney=0+0−4y = 0 + 0 − 4\newliney=−4y = −4
  3. Calculate y value: The y-intercept of the parabola is the point (0,y)(0, y), where yy is the value we just calculated.\newlineTherefore, the y-intercept is (0,−4)(0, -4).

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