Find the y-intercept of the parabola y = x^2 − 2x − 29/5 . Simplify your answer and write it as a proper fraction, improper fraction, or integer. _____

Evaluate Function at x=0: To find the y-intercept of the parabola, we need to evaluate the function y = x^2 - 2x - 29/5 at x = 0.Substitute x=0: Substitute x = 0 into the equation y = x^2 - 2x - 29/5 to find the y-intercept. y = (0)^2 - 2(0) - 29/5 y = 0 - 0 - 29/5 y = -29/5Calculate y-intercept: The y-intercept of the parabola is the point (0, y) where y is the value we just calculated. Therefore, the y-intercept is (0, -29/5).

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Find the $y$ -intercept of the parabola $y = x^2 - 2x - \frac{29}{5}$ . $\newline$ Simplify your answer and write it as a proper fraction, improper fraction, or integer. $\newline$ _____

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Algebra 2

Characteristics of quadratic functions: equations

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Q. Find the

y

-intercept of the parabola

y = x^2 - 2x - \frac{29}{5}

\newline

Simplify your answer and write it as a proper fraction, improper fraction, or integer.

\newline

_____

Evaluate Function at $x=0$ : To find the $y$ -intercept of the parabola, we need to evaluate the function $y = x^2 - 2x - \frac{29}{5}$ at $x = 0$ .
Substitute $x=0$ : Substitute $x = 0$ into the equation $y = x^2 - 2x - \frac{29}{5}$ to find the y-intercept. $\newline$ $y = (0)^2 - 2(0) - \frac{29}{5}$ $\newline$ $y = 0 - 0 - \frac{29}{5}$ $\newline$ $y = -\frac{29}{5}$
Calculate y-intercept: The y-intercept of the parabola is the point $(0, y)$ where $y$ is the value we just calculated. $\newline$ Therefore, the y-intercept is $(0, -\frac{29}{5})$ .