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Find the sum of the positive terms of the arithmetic sequence 
85,78,71,dots

Find the sum of the positive terms of the arithmetic sequence 85,78,71, 85,78,71, \ldots

Full solution

Q. Find the sum of the positive terms of the arithmetic sequence 85,78,71, 85,78,71, \ldots
  1. Identify Decreasing Pattern: The sequence is decreasing by 77 each time (8578=785 - 78 = 7). To find the sum of the positive terms, we need to find the last positive term in the sequence.
  2. Find Last Positive Term: The nnth term of an arithmetic sequence is given by an=a1+(n1)da_n = a_1 + (n - 1)d, where a1a_1 is the first term and dd is the common difference. We need to solve for nn when an>0a_n > 0.
  3. Set Up Inequality: Let's set up the inequality: 85+(n1)(7)>085 + (n - 1)(-7) > 0.
  4. Solve Inequality: Solving the inequality: 857n+7>085 - 7n + 7 > 0.
  5. Simplify Inequality: Simplify the inequality: 927n>092 - 7n > 0.
  6. Calculate nn Value: Divide by 7-7 and reverse the inequality sign: n<927n < \frac{92}{7}.
  7. Find 1313th Term: Calculate nn: n<13.14n < 13.14. Since nn must be a whole number, the last positive term is when n=13n = 13.
  8. Use Arithmetic Series Formula: Now we find the 13th13^{\text{th}} term: 85+(131)(7)=8584=185 + (13 - 1)(-7) = 85 - 84 = 1.
  9. Substitute Values: The sum of an arithmetic series is given by Sn=n2(a1+an)S_n = \frac{n}{2} * (a_1 + a_n). We'll use this formula to find the sum of the first 1313 terms.
  10. Calculate Sum: Substitute the values into the formula: S13=132×(85+1)S_{13} = \frac{13}{2} \times (85 + 1).
  11. Calculate Sum: Substitute the values into the formula: S13=132×(85+1)S_{13} = \frac{13}{2} \times (85 + 1).Calculate the sum: S13=6.5×86S_{13} = 6.5 \times 86.
  12. Calculate Sum: Substitute the values into the formula: S13=132×(85+1)S_{13} = \frac{13}{2} \times (85 + 1).Calculate the sum: S13=6.5×86S_{13} = 6.5 \times 86.Final calculation: S13=559S_{13} = 559.

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