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One angle of a triangle measures 110110^\circ. The other two angles are in a ratio of 2:52:5. What are the measures of those two angles? \newline\underline{\hspace{1cm}}^\circ and \underline{\hspace{1cm}}^\circ

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Q. One angle of a triangle measures 110110^\circ. The other two angles are in a ratio of 2:52:5. What are the measures of those two angles? \newline\underline{\hspace{1cm}}^\circ and \underline{\hspace{1cm}}^\circ
  1. Identify Known and Unknown: First, let's identify what we know and what we need to find out. We know that one angle of the triangle measures 110110^\circ, and we need to find the measures of the other two angles, which are in a ratio of 2:52:5. Since the sum of angles in any triangle is 180180^\circ, we can set up an equation to find the values of the other two angles.
  2. Set Up Equation: Let's denote the smaller angle as 2x2x and the larger angle as 5x5x. According to the angle sum property of a triangle, the sum of the angles should be 180180^\circ. Therefore, we can write the equation as:\newline110+2x+5x=180110^\circ + 2x + 5x = 180^\circ.
  3. Combine Like Terms: Now, let's combine like terms (2x2x and 5x5x) to simplify the equation:\newline110+7x=180.110^\circ + 7x = 180^\circ.\newlineNext, we will subtract 110110^\circ from both sides to solve for 7x7x:\newline7x=180110.7x = 180^\circ - 110^\circ.
  4. Subtract to Solve for x: Performing the subtraction, we get:\newline7x=707x = 70^\circ.\newlineNow, we will divide both sides by 77 to find the value of xx:\newlinex=707x = \frac{70^\circ}{7}.
  5. Divide to Find x: Calculating the value of x, we get:\newlinex=10x = 10^\circ.\newlineNow that we have the value of x, we can find the measures of the other two angles by multiplying x by the respective ratio numbers:\newline2x=2×10=202x = 2 \times 10^\circ = 20^\circ,\newline5x=5×10=505x = 5 \times 10^\circ = 50^\circ.

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