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Find the sum of the infinite geometric series.\newline82457225216125+-8 - \frac{24}{5} - \frac{72}{25} - \frac{216}{125} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______

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Q. Find the sum of the infinite geometric series.\newline82457225216125+-8 - \frac{24}{5} - \frac{72}{25} - \frac{216}{125} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______
  1. Identify Terms: Identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term aa is 8-8.\newlineTo find the common ratio rr, we divide the second term by the first term.\newliner=245/(8)=35r = \frac{-24}{5} / (-8) = \frac{3}{5}
  2. Check Convergence: Check if the absolute value of the common ratio is less than 11 to ensure the series converges.\newline35=35|\frac{3}{5}| = \frac{3}{5}, which is less than 11, so the series converges.
  3. Use Sum Formula: Use the formula for the sum of an infinite geometric series, which is S=a1rS = \frac{a}{1 - r}, where SS is the sum, aa is the first term, and rr is the common ratio.\newlineS=81(35)S = \frac{-8}{1 - (\frac{3}{5})}
  4. Calculate Sum: Calculate the sum using the formula.\newlineS=81(35)S = \frac{-8}{1 - \left(\frac{3}{5}\right)}\newlineS=825S = \frac{-8}{\frac{2}{5}}\newlineS=8×(52)S = -8 \times \left(\frac{5}{2}\right)\newlineS=402S = \frac{-40}{2}\newlineS=20S = -20

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