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Find the equation of the hyperbola with the vertices 
(0,3)(10,3) and the asymptotes 
y=2//5x+1 and 
y=-2//5x+5

66. Find the equation of the hyperbola with the vertices (0,3)(10,3) (0,3)(10,3) and the asymptotes y=2/5x+1 y=2 / 5 x+1 and y=2/5x+5 y=-2 / 5 x+5

Full solution

Q. 66. Find the equation of the hyperbola with the vertices (0,3)(10,3) (0,3)(10,3) and the asymptotes y=2/5x+1 y=2 / 5 x+1 and y=2/5x+5 y=-2 / 5 x+5
  1. Identify Hyperbola Equation Form: Identify the standard form of the equation for a hyperbola with a horizontal transverse axis.\newlineStandard form of equation for a hyperbola with a horizontal transverse axis: \newline(xh)2/a2(yk)2/b2=1(x-h)^2/a^2 - (y-k)^2/b^2 = 1
  2. Determine Center of Hyperbola: Determine the center (h,k)(h, k) of the hyperbola.\newlineThe vertices are (0,3)(0, 3) and (10,3)(10, 3). The center is the midpoint of the line segment joining the vertices.\newlineh=(0+10)/2=5h = (0 + 10)/2 = 5\newlinek=(3+3)/2=3k = (3 + 3)/2 = 3
  3. Calculate Semi-Major Axis: Calculate the value of the semi-major axis aa.aa is the distance from the center to a vertex.a=102=5a = \frac{10}{2} = 5
  4. Determine Asymptote Slope: Determine the slope of the asymptotes to find the value of bb. The slopes of the asymptotes for a horizontal hyperbola are given by ±ba\pm\frac{b}{a}. The given slopes are ±25\pm\frac{2}{5}. ba=25\frac{b}{a} = \frac{2}{5} Since we already know a=5a = 5, we can solve for bb. b=(25)ab = \left(\frac{2}{5}\right) \cdot a b=(25)5b = \left(\frac{2}{5}\right) \cdot 5 b=2b = 2
  5. Write Standard Form Equation: Write the equation of the hyperbola in standard form using the values of hh, kk, aa, and bb. Substitute the values into (xh)2/a2(yk)2/b2=1(x-h)^2/a^2 - (y-k)^2/b^2 = 1. (x5)2/52(y3)2/22=1(x - 5)^2/5^2 - (y - 3)^2/2^2 = 1 Simplify the equation. (x5)2/25(y3)2/4=1(x - 5)^2/25 - (y - 3)^2/4 = 1

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