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Find the equation of the axis of symmetry for the parabola y=x2+xy = x^2 + x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x2+xy = x^2 + x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_
  1. Identify Coefficients: Identify the coefficients of the quadratic equation.\newlineThe given parabola is y=x2+xy = x^2 + x. This can be compared to the standard form of a quadratic equation, which is y=ax2+bx+cy = ax^2 + bx + c. Here, a=1a = 1, b=1b = 1, and cc is not given because it is 00.
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola given by y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Substitute Values: Substitute the values of aa and bb into the formula.\newlinea=1a = 1 and b=1b = 1, so the axis of symmetry is x=1(21)=12x = -\frac{1}{(2 \cdot 1)} = -\frac{1}{2}.
  4. Write Equation: Write the equation of the axis of symmetry.\newlineThe axis of symmetry is a vertical line, so its equation is x=constantx = \text{constant}. In this case, the constant is 12-\frac{1}{2}. Therefore, the equation of the axis of symmetry is x=12x = -\frac{1}{2}.

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