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Find the equation of the axis of symmetry for the parabola y=x2+3710y = x^2 + \frac{37}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____

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Q. Find the equation of the axis of symmetry for the parabola y=x2+3710y = x^2 + \frac{37}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____
  1. Identify coefficients: Identify the coefficients of the quadratic equation.\newlineThe given parabola is y=x2+3710y = x^2 + \frac{37}{10}. This can be compared to the standard form of a quadratic equation, which is y=ax2+bx+cy = ax^2 + bx + c. In this case, a=1a = 1, b=0b = 0 (since there is no xx term), and c=3710c = \frac{37}{10}.
  2. Use axis of symmetry formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola given by y=ax2+bx+cy = ax^2 + bx + c is x=−b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Calculate axis of symmetry: Calculate the axis of symmetry.\newlineSubstitute a=1a = 1 and b=0b = 0 into the formula x=−b2ax = -\frac{b}{2a}.\newlinex=−02×1x = -\frac{0}{2 \times 1}\newlinex=02x = \frac{0}{2}\newlinex=0x = 0\newlineThe axis of symmetry is the vertical line x=0x = 0.

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