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Find the equation of the axis of symmetry for the parabola y=x252y = x^2 - \frac{5}{2}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x252y = x^2 - \frac{5}{2}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_
  1. Identify values of aa, bb, cc: The general form of a quadratic equation is y=ax2+bx+cy = ax^2 + bx + c. We need to identify the values of aa, bb, and cc in the given equation y=x252y = x^2 - \frac{5}{2}.
  2. Compare with general form: Comparing y=x252y = x^2 - \frac{5}{2} with y=ax2+bx+cy = ax^2 + bx + c, we can see that a=1a = 1, b=0b = 0, and c=52c = -\frac{5}{2}. The coefficient bb is zero because there is no xx term in the given equation.
  3. Find axis of symmetry: The axis of symmetry for a parabola given by y=ax2+bx+cy = ax^2 + bx + c is found using the formula x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  4. Substitute values and calculate: Substitute a=1a = 1 and b=0b = 0 into the formula x=b2ax = -\frac{b}{2a} to find the axis of symmetry.\newlinex=02×1x = -\frac{0}{2 \times 1}\newlinex=0x = 0\newlineThe axis of symmetry for the parabola y=x252y = x^2 - \frac{5}{2} is x=0x = 0.

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