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Find the equation of the axis of symmetry for the parabola y=x2+6x+9y = x^2 + 6x + 9. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x2+6x+9y = x^2 + 6x + 9. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_
  1. Find Axis of Symmetry: The axis of symmetry for a parabola given by the equation y=ax2+bx+cy = ax^2 + bx + c is found using the formula x=−b2ax = -\frac{b}{2a}. We substitute the values of aa and bb into this formula to find the axis of symmetry. x=−b2a=−62⋅1=−62=−3x = -\frac{b}{2a} = -\frac{6}{2\cdot 1} = -\frac{6}{2} = -3
  2. Calculate xx Value: The equation of the axis of symmetry is therefore x=−3x = -3. This is a vertical line that passes through the vertex of the parabola and divides it into two symmetrical halves.

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