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Find the equation of the axis of symmetry for the parabola y=x29y = x^2 - 9. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____

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Q. Find the equation of the axis of symmetry for the parabola y=x29y = x^2 - 9. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____
  1. Identify values of aa and bb: The equation of a parabola in the form y=ax2+bx+cy = ax^2 + bx + c has an axis of symmetry given by the formula x=b2ax = -\frac{b}{2a}. First, we need to identify the values of aa and bb in the given equation y=x29y = x^2 − 9.
  2. Compare with standard form: Comparing y=x29y = x^2 - 9 with the standard form y=ax2+bx+cy = ax^2 + bx + c, we can see that a=1a = 1 and b=0b = 0, since there is no xx term in the equation y=x29y = x^2 - 9. The value of cc is 9-9, but it is not needed to find the axis of symmetry.
  3. Substitute into formula: Now we substitute the values of aa and bb into the formula for the axis of symmetry: x=b/(2a)x = -b/(2a). This gives us x=0/(2×1)x = -0/(2\times1).
  4. Simplify expression: Simplifying the expression 0(21)-\frac{0}{(2\cdot1)} gives us x=02x = \frac{0}{2}, which further simplifies to x=0x = 0. Therefore, the axis of symmetry for the parabola y=x29y = x^2 − 9 is the line x=0x = 0.

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