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Find the equation of the axis of symmetry for the parabola y=x2−4x+135y = x^2 - 4x + \frac{13}{5}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____

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Q. Find the equation of the axis of symmetry for the parabola y=x2−4x+135y = x^2 - 4x + \frac{13}{5}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____
  1. Substitute values into formula: The axis of symmetry for a parabola given by the equation y=ax2+bx+cy = ax^2 + bx + c is x=−b2ax = -\frac{b}{2a}.\newlineWe already have the values of aa and bb from the previous step:\newlinea=1a = 1\newlineb=−4b = -4\newlineNow we substitute these values into the formula for the axis of symmetry:\newlinex=−−42×1x = -\frac{-4}{2 \times 1}
  2. Perform calculation: Perform the calculation to find the value of xx for the axis of symmetry:\newlinex=42×1x = \frac{4}{2 \times 1}\newlinex=42x = \frac{4}{2}\newlinex=2x = 2

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