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Find the equation of the axis of symmetry for the parabola y=x2+6x+7110y = x^2 + 6x + \frac{71}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_

Full solution

Q. Find the equation of the axis of symmetry for the parabola y=x2+6x+7110y = x^2 + 6x + \frac{71}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_
  1. Identify Coefficients: Identify the coefficients of the quadratic equation.\newlineThe quadratic equation is given in the form y=ax2+bx+cy = ax^2 + bx + c. For the parabola y=x2+6x+7110y = x^2 + 6x + \frac{71}{10}, we can identify the coefficients as follows:\newlinea=1a = 1 (coefficient of x2x^2)\newlineb=6b = 6 (coefficient of xx)\newlinec=7110c = \frac{71}{10} (constant term)
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola in the form y=ax2+bx+cy = ax^2 + bx + c is given by the formula x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Substitute Values into Formula: Substitute the values of aa and bb into the formula.\newlineUsing a=1a = 1 and b=6b = 6, we get:\newlinex=b2ax = -\frac{b}{2a}\newlinex=62×1x = -\frac{6}{2 \times 1}\newlinex=62x = -\frac{6}{2}\newlinex=3x = -3\newlineThe equation of the axis of symmetry is x=3x = -3.

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