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Find the equation of the axis of symmetry for the parabola y=x2+3xy = x^2 + 3x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x2+3xy = x^2 + 3x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_
  1. Identify Coefficients: Identify the coefficients of the quadratic equation.\newlineThe given parabola is in the form y=ax2+bx+cy = ax^2 + bx + c. For the equation y=x2+3xy = x^2 + 3x, we can see that a=1a = 1 and b=3b = 3. There is no constant term, so c=0c = 0.
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola in the form y=ax2+bx+cy = ax^2 + bx + c is given by the formula x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Substitute Values: Substitute the values of aa and bb into the formula.\newlineSubstituting a=1a = 1 and b=3b = 3 into the formula x=b/(2a)x = -b/(2a), we get:\newlinex=3/(21)x = -3/(2\cdot1)\newlinex=32x = -\frac{3}{2}
  4. Write Axis of Symmetry Equation: Write the equation of the axis of symmetry.\newlineThe axis of symmetry is a vertical line, so its equation is of the form x=constantx = \text{constant}. From the previous step, we found that constant to be 32-\frac{3}{2}. Therefore, the equation of the axis of symmetry is:\newlinex=32x = -\frac{3}{2}

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