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Find the domain of the function 
f(x)=(1)/(sqrt(2-2x-x^(2))). (Enter your answer using interval notation.)

Find the domain of the function f(x)=122xx2 f(x)=\frac{1}{\sqrt{2-2 x-x^{2}}} . (Enter your answer using interval notation.)

Full solution

Q. Find the domain of the function f(x)=122xx2 f(x)=\frac{1}{\sqrt{2-2 x-x^{2}}} . (Enter your answer using interval notation.)
  1. Identify Inner Function: Identify the inner function within the square root to determine where it is non-negative, as the square root function requires non-negative inputs for real number outputs.
  2. Rewrite in Standard Form: Rewrite the quadratic equation in standard form and identify values of aa, bb, and cc.
  3. Check Discriminant: Use the discriminant formula, b24acb^2 - 4ac, to check if the quadratic equation has real roots, which will help in finding the intervals where the function under the square root is non-negative.
  4. Solve for Roots: Since the discriminant is positive, solve for the roots of the equation using the quadratic formula, x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
  5. Determine Non-Negative Intervals: Determine the intervals where the function under the square root, 22xx22 - 2x - x^2, is non-negative. This is between the roots because the parabola opens downwards (a=1a = -1).
  6. Write Domain: Write the domain of f(x)f(x) using interval notation, considering where the function under the square root is non-negative.

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