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Find the discriminant. \newline2t2+4t+2=02t^2 + 4t + 2 = 0\newline______

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Q. Find the discriminant. \newline2t2+4t+2=02t^2 + 4t + 2 = 0\newline______
  1. Identify coefficients: Identify the coefficients aa, bb, and cc from the quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0. For the equation 2t2+4t+2=02t^2 + 4t + 2 = 0, we have: a=2a = 2 b=4b = 4 c=2c = 2
  2. Recall discriminant formula: Recall the formula for the discriminant of a quadratic equation, which is D=b24acD = b^2 - 4ac.
  3. Substitute values into formula: Substitute the identified values of aa, bb, and cc into the discriminant formula.D=424×2×2D = 4^2 - 4 \times 2 \times 2
  4. Calculate discriminant: Perform the calculations to find the value of the discriminant.\newlineD=164×2×2D = 16 - 4 \times 2 \times 2\newlineD=1616D = 16 - 16\newlineD=0D = 0

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