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Find the derivative of the following function.

y=3^(-5x^(2))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=35x2 y=3^{-5 x^{2}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=35x2 y=3^{-5 x^{2}} \newlineAnswer: y= y^{\prime}=
  1. Identify Functions: We are given the function y=35x2y=3^{-5x^{2}}. To find the derivative, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Derivative of Outer Function: First, let's identify the outer function and the inner function. The outer function is f(u)=3uf(u) = 3^u, and the inner function is u(x)=5x2u(x) = -5x^2. We will need to take the derivative of both of these functions.
  3. Derivative of Inner Function: The derivative of the outer function f(u)=3uf(u) = 3^u with respect to uu is f(u)=3uln(3)f'(u) = 3^u \cdot \ln(3), using the fact that the derivative of axa^x with respect to xx is axln(a)a^x \cdot \ln(a).
  4. Apply Chain Rule: The derivative of the inner function u(x)=5x2u(x) = -5x^2 with respect to xx is u(x)=ddx(5x2)=10xu'(x) = \frac{d}{dx}(-5x^2) = -10x.
  5. Substitute Derivatives: Now we apply the chain rule. The derivative of yy with respect to xx is y=f(u)u(x)y' = f'(u) \cdot u'(x). Substituting the derivatives we found, we get y=(35x2ln(3))(10x)y' = (3^{-5x^2} \cdot \ln(3)) \cdot (-10x).
  6. Simplify Final Derivative: Simplify the expression to get the final derivative. y=10xln(3)35x2y' = -10x \cdot \ln(3) \cdot 3^{-5x^2}.

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