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Let’s check out your problem:
Find the are length.
\newline
A.
98
π
3
\frac{98 \pi}{3}
3
98
π
\newline
B.
75
π
4
\frac{75 \pi}{4}
4
75
π
\newline
C.
19
π
3
\frac{19 \pi}{3}
3
19
π
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Home
Math Problems
Algebra 2
Sum of finite series not start from 1
Full solution
Q.
Find the are length.
\newline
A.
98
π
3
\frac{98 \pi}{3}
3
98
π
\newline
B.
75
π
4
\frac{75 \pi}{4}
4
75
π
\newline
C.
19
π
3
\frac{19 \pi}{3}
3
19
π
Add Arc Lengths:
Add up the arc lengths given in options A, B, and C.
\newline
(
98
π
3
)
+
(
75
π
4
)
+
(
19
π
3
)
(\frac{98\pi}{3}) + (\frac{75\pi}{4}) + (\frac{19\pi}{3})
(
3
98
π
)
+
(
4
75
π
)
+
(
3
19
π
)
Find Common Denominator:
Find a common denominator to add the fractions.
\newline
Common denominator is
12
12
12
.
\newline
4
×
98
π
4
×
3
\frac{4 \times 98 \pi}{4 \times 3}
4
×
3
4
×
98
π
+
3
×
75
π
3
×
4
\frac{3 \times 75 \pi}{3 \times 4}
3
×
4
3
×
75
π
+
4
×
19
π
4
×
3
\frac{4 \times 19 \pi}{4 \times 3}
4
×
3
4
×
19
π
Multiply Numerators:
Multiply the numerators by the respective multipliers.
\newline
(
392
π
12
)
+
(
225
π
12
)
+
(
76
π
12
)
(\frac{392 \pi}{12}) + (\frac{225 \pi}{12}) + (\frac{76 \pi}{12})
(
12
392
π
)
+
(
12
225
π
)
+
(
12
76
π
)
Add Numerators:
Add the numerators together.
\newline
392
π
+
225
π
+
76
π
=
693
π
392 \pi + 225 \pi + 76 \pi = 693 \pi
392
π
+
225
π
+
76
π
=
693
π
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Choices:Choices:
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Question
Find the first three partial sums of the series.
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\newline
S
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=
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\newline
S
2
=
S_2 =
S
2
=
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\newline
S
3
=
S_3 =
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Find the third partial sum of the series.
\newline
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21
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27
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33
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\newline
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\newline
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\newline
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=
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2
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\newline
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+
27
64
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\newline
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[A]converge
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[B]diverge
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