Substitute and Evaluate: First, let's try to directly substitute the value of x with −4 into the function to see if it results in an indeterminate form or not.Substitute x=−4 into (7x+28)/(x2+x−12).limx→−4(7x+28)/(x2+x−12)= (7(−4)+28)/((−4)2+(−4)−12)= (−28+28)/(16−4−12)= 0/0Since we get 0/0, which is an indeterminate form, we cannot directly evaluate the limit by substitution.
Factorize Denominator: Next, we should try to factor the numerator and the denominator to see if there are any common factors that can be canceled out.Factor the quadratic expression in the denominator x2+x−12.x2+x−12 can be factored into (x+4)(x−3).Now, let's rewrite the limit expression with the factored form of the denominator.limx→−4(x+4)(x−3)7x+28
Factorize Numerator: Notice that the numerator 7x+28 can also be factored because it is a common factor of 7.Factor out the common factor of 7 from the numerator.7x+28 can be factored into 7(x+4).Now, let's rewrite the limit expression with the factored form of the numerator.limx→−4(x+4)(x−3)7(x+4)
Cancel Common Factor: We can now cancel out the common factor (x+4) from the numerator and the denominator, as long as x is not equal to −4. Since we are taking the limit as x approaches −4, not at x=−4, we can cancel the factors.Cancel the (x+4) term from the numerator and the denominator.limx→−4(x−3)7
Final Substitution: Now that we have a simplified expression, we can substitute x=−4 into the limit to find the value.Substitute x=−4 into (x−3)7.limx→−4(x−3)7= ((−4)−3)7= (−7)7= −1The limit exists and is equal to −1.