Identify Components: Identify the components of the function that will require the use of the product rule for differentiation.The function f(x)=2xcos(x) is a product of two functions, g(x)=2x and h(x)=cos(x).
Recall Product Rule: Recall the product rule for differentiation, which states that if f(x)=g(x)⋅h(x), then f′(x)=g′(x)⋅h(x)+g(x)⋅h′(x). We will apply this rule to find the derivative of f(x)=2xcos(x).
Differentiate g(x): Differentiate g(x)=2x with respect to x. The derivative of g(x) with respect to x is g′(x)=dxd(2x)=2.
Differentiate h(x): Differentiate h(x)=cos(x) with respect to x. The derivative of h(x) with respect to x is h′(x)=dxd(cos(x))=−sin(x).
Apply Product Rule: Apply the product rule using the derivatives found in the previous steps.Using g′(x)=2 and h′(x)=−sin(x), we get f′(x)=g′(x)⋅h(x)+g(x)⋅h′(x)=2⋅cos(x)+2x⋅(−sin(x)).
Simplify Derivative: Simplify the expression for the derivative.f′(x)=2⋅cos(x)−2x⋅sin(x).This is the derivative of the function f(x)=2xcos(x).
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