Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

f(x,y)=x^(2)+y^(2)+4xy+4x+5y+1=

f(x,y)=x2+y2+4xy+4x+5y+1= f(x, y)=x^{2}+y^{2}+4 x y+4 x+5 y+1=

Full solution

Q. f(x,y)=x2+y2+4xy+4x+5y+1= f(x, y)=x^{2}+y^{2}+4 x y+4 x+5 y+1=
  1. Substitute Values: Substitute 00 for xx and yy in f(x,y)=x2+y2+4xy+4x+5y+1f(x,y) = x^2 + y^2 + 4xy + 4x + 5y + 1.\newlinef(0,0)=(0)2+(0)2+4(0)(0)+4(0)+5(0)+1f(0,0) = (0)^2 + (0)^2 + 4\cdot(0)\cdot(0) + 4\cdot(0) + 5\cdot(0) + 1
  2. Simplify Expression: Simplify the expression. f(0,0)=0+0+0+0+0+1f(0,0) = 0 + 0 + 0 + 0 + 0 + 1
  3. Add Terms: Add up all the terms.\newlinef(0,0)=1f(0,0) = 1

More problems from Composition of linear and quadratic functions: find a value